car license plate character recognition using neural network

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sneha
sneha el 9 de Abr. de 2012
Comentada: Image Analyst el 23 de Feb. de 2020
sir again i have one big query...iwant to recognize the license plate charactyer using neural network...but really i m too much confuse that how could i find the link between segmented characters and neural network....means i m unable to find syntax of giving segmented characters as i/p of neural...plese ans me..if any idea...please.........any one help me.....

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Geoff
Geoff el 10 de Abr. de 2012
I have not done plate recognition, and have only dabbled in neural networks, but I would expect that you need to translate your segmented characters into a vector. That means you first need to standardise the width and height of each segment, which will involve resampling. I would also expect some kind of image normalisation.
Then you can supply each segment as a 1-dimensional vector. The number of pixels in that vector is the number of inputs in your neural network. From memory, the neural network expects inputs along the rows, and each individual training case in the columns. So you would insert each segment-vector into a unique column of your input matrix. The corresponding training output vector, of course, is the character that each segment-vector represents.
Something like that, anyway =)
  1 comentario
sneha
sneha el 11 de Abr. de 2012
hello sir how can i convert my segmented char into vectors??any matlab syntax?

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Más respuestas (6)

Swati
Swati el 10 de Abr. de 2012
This one is the code for you,,,of Number plate recognition,,,I have earlier work on this one,,,,in this take a image of car,,then take seperate image of its no plate (for ex,,if no is MP 09-T_456,,,,so take seperate image of M then P,,,then,,,T,,,so on,,,all will b in a single folder n in .bmp format)
may ths one helps you,,,
{I = imread('car.jpg');
I2 = rgb2gray(I);
I4 = im2bw(I2, 0.2);
bw = bwareaopen(I4, 500);
se = strel('disk',15);
bw = imclose(bw,se);
bw = imfill(bw,[1 1]);
[B,L] = bwboundaries(bw,4);
imshow(label2rgb(L, @jet, [.5 .5 .5]))
hold on
for k = 1:length(B)
boundary = B{k};
plot(boundary(:,2),boundary(:,1),'w','LineWidth',2)
end
stats = regionprops(L,'Area','Centroid');
for k = 1:length(B)
boundary = B{k};
delta_sq = diff(boundary).^2;
perimeter = sum(sqrt(sum(delta_sq,2)));
area = stats(k).Area;
metric = 27*area/perimeter^2;
metric_string = sprintf('%2.2f',metric);
if metric >= 0.9 && metric <= 1.1
centroid = stats(k).Centroid;
plot(centroid(1),centroid(2),'ko');
goalboundary = boundary;
s = min(goalboundary, [], 1);
e = max(goalboundary, [], 1);
goal = imcrop(I4,[s(2) s(1) e(2)-s(2) e(1)-s(1)]);
end
text(boundary(1,2)-35,boundary(1,1)+13,...
metric_string,'Color','g',...
'FontSize',14,'FontWeight','bold');
end
goal = ~goal;
goal(256,256) = 0;
figure;
imshow(goal);
w = imread('P.bmp');
w = ~w;
C=real(ifft2(fft2(goal).*fft2(rot90(w,2),256,256)));
thresh = 240;
figure;
imshow(C > thresh);
  4 comentarios
Archit Save
Archit Save el 16 de En. de 2016
Editada: Archit Save el 16 de En. de 2016
i am getting an error...'Undefined function or variable goal'
Image Analyst
Image Analyst el 16 de En. de 2016
You probably renamed or misspelled a variable somewhere. What variable is given in the call to imshow() just prior to that? If goal weren't a variable, then the imshow() would have thrown an error before the fft line.

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sneha
sneha el 10 de Abr. de 2012
thank you very much swati and geoff..........i will try on both of your ways.....thanks a lot....

sneha
sneha el 11 de Abr. de 2012
hey rakshita can u mail me ur code...i have run your code given above but it gives me errorlik this... Undefined function or variable 'y_cor1'.
Error in ==> mathworklpr at 276 lp=d(y_cor1:x_cor2,x_cor1:y_cor2);
i cant go ahead....i want to recognize charctrs with neural net...plz help

sneha
sneha el 14 de Abr. de 2012
hi now i m succesfully segment license plate chara..now m going 2 recognize them using OCR....in MATLAB.... plz anyone can help me....its urgent...pleaseeee..........
  1 comentario
Derick kundukulam
Derick kundukulam el 23 de Nov. de 2014
did the code work.. even i'm gettin the error C=real(ifft2(fft2(goal).*fft2(rot90(w,2),256,256)));

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Image Analyst
Image Analyst el 14 de Abr. de 2012

Imtiaz Hussain
Imtiaz Hussain el 23 de Feb. de 2020
this is my research topic plz can you help me?

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