how to divide the RGB color space into 64 cubic blocks ?

Hello

can any one tell me how to to divide the RGB color space into 64 cubic blocks with four equal partitions along each dimension.

[John D'Errico]

How? You do it. Whats the problem? All that matters is what you will do with it, and only you know that.

[SAM]

i want to compute color distribution, distinguishing multi-colored images from monochromatic, sepia or simply low contrast images.

and i want to use each cube as a sample point for my further process.

Answer 1

[Image Analyst]

Like John said, it depends on what you will do with it - how you will use it. If you want to make a histogram, you need to find out what block you're in

for col = 1 : cols
  for row = 1 : rows
    % Get the RGB values of the image.
    rValue = rgbImage(row, col, 1);
    gValue = rgbImage(row, col, 2);
    bValue = rgbImage(row, col, 3);
    % Find out which of the 64 blocks they belong to.
    % Block numbers range from 1 to 4.
    rBlock = ceil(rValue / 64);
    gBlock = ceil(gValue / 64);
    bBlock = ceil(bValue / 64);
    % Increment the histogram.
    rgbHist(rBlock, gBlock, bBlock) = rgbHist(rBlock, gBlock, bBlock) + 1;
  end
end

Also see attached file.

[SAM]

thanks for your answer.

can you please tell me What Is rgbHist in above program?

[Image Analyst]

It's a histogram. Sounds like what you want.

[SAM]

I want 64 cubes and i will use each cube as a sample point for my further process.

[Image Analyst]

I don't know what that means exactly, but good luck to you.

[SAM]

Thanks For your Help And Support. i really appreciate your helping Nature Towards the Biginners ...........