whats the meaning of this statement average = sum ( sum ( x(:,:) ) ) / n / n; ?

i am using this formula for increasing the contrast of the image. this is the formula used to calculate the average value of the after getting the size of the array of the image by using n=size(x,1); ? where x is the image on which we are working..

Answer 1

[Daniel Shub]

The meaning of the statement

average = sum ( sum ( x(:,:) ) ) / n / n;

is that whoever wrote the code knows very little about MATLAB. Assuming x is an n x n matrix, the code calculates the average/mean by summing over all the columns to create a row of sums and then summing across the row to get the total sum of the matrix. It then divides by n twice to get the average. The same thing can be done much more clearly with

average = mean(x(:));

where (:) is needed to turn a matrix into a column vector.

[Gursheen]

wow..thanks a lot.. THERE IS ALSO A CODE THAT FOLLOWS WHICH NEEDS UNDERSTANDING...PLEASE HELP ME OUT WITH THIS AS WELL. HERE GRAY IS THE NAME OF THE IMAGE gray=double(gray);

gray3d(1,:,:) = circshift ( gray, [ -1, -1 ] ); gray3d(2,:,:) = circshift ( gray, [ -1, 0 ] ); gray3d(3,:,:) = circshift ( gray, [ -1, 1 ] ); gray3d(4,:,:) = circshift ( gray, [ 0, -1 ] ); gray3d(5,:,:) = circshift ( gray, [ 0, 1 ] ); gray3d(6,:,:) = circshift ( gray, [ 1, -1 ] ); gray3d(7,:,:) = circshift ( gray, [ 1, 0 ] ); gray3d(8,:,:) = circshift ( gray, [ 1, 1 ] );

gray_average = sum ( gray3d ) / 8.0;

% The SUM operation on an (L,M,N) array returns a (1,M,N) array.

gray_average_2d(1:m,1:n) = gray_average(1,1:m,1:n);

I AM UNABLE TO UNDERSTAND THE CODE...PLEASE HELP....THANKS ALOT