how to make a matrix grow inside a parfor loop?

Hi, i would like to do this in a parfor loop:
S=[];
for n=in:fin
[s,trueorfalse]=somefunction(someinput);
if trueorfalse
S=[S;s];
end
end
I cannot preallocate because i don't know how much big S will be. I tried some thing but nothing worked so far.
Hope you could help me.

 Respuesta aceptada

Edric Ellis
Edric Ellis el 7 de Mayo de 2014
Editada: Edric Ellis el 7 de Mayo de 2014
You should be able to do this. For example, the following works correctly:
S = [];
parfor idx = 1:10
r = rand();
if r > 0.5
S = [S, r];
end
end

3 comentarios

kira
kira el 7 de Mayo de 2014
that is exactly what i tried, but i get an error, about the way S is used.
Edric Ellis
Edric Ellis el 8 de Mayo de 2014
Did you try precisely that code? That code works correctly all the way back even to MATLAB R2008a. Which version did you try it in?
kira
kira el 9 de Mayo de 2014
hi, i tried my original code again, changing for by parfor an now it works... ?_?
thanks to all for your help...

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Más respuestas (1)

Brian B
Brian B el 7 de Mayo de 2014
You could make S a cell array in the loop, then create a matrix afterward:
somefunction = @(x)deal(x,rand(1)<0.3);
S=cell(100,1);
parfor n=1:100
[s,trueorfalse]=feval(somefunction, n);
if trueorfalse
%S=[S;s];
S{n} = s;
end
end
S = cell2mat(S);

1 comentario

kira
kira el 7 de Mayo de 2014
i could this with S=sparse(fin,dim), but variable fin is very big (O(2^m))

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