How can I find the largest number

Hi, I have 3 numbers and I have to find the biggest one, what is the best way? This is the code:
T=200
if isempty(counter) || counter >= T
counter=0;
d1=0.1
d2=0.2
d3=0.6
else counter=counter+1
if counter>0
if d1=max([d1,d2,d3)]
...
elseif d2=max([d1,d2,d3)]
...
elseif d3=max([d1,d2,d3)]
...
end
end
end
But this code doesn't work, thank you

3 comentarios

Mischa Kim
Mischa Kim el 2 de Jul. de 2014
Do you only need the number (0.6) or do you want to know the specific variable ( d3 )?
I just need to know which is the greater one in order to define another variable, for example:
if d1=max([d1,d2,d3)]
V=V1
elseif d2=max([d1,d2,d3)]
V=V1
elseif
...
Roberto Calandra
Roberto Calandra el 2 de Jul. de 2014
Remember that with d1=max([d1,d2,d3]) you are assigning a variable to d1but what you want is checking for equality as in d1==max([d1,d2,d3])

Iniciar sesión para comentar.

 Respuesta aceptada

Elias Gule
Elias Gule el 2 de Jul. de 2014
numbers = [num1 num2 num3]; % the array of numbers from which to search
maxVal = max(numbers); % the highest number

Más respuestas (2)

Roberto Calandra
Roberto Calandra el 2 de Jul. de 2014
Something like this?
switch max([d1,d2,d3])
case {d1}
V=V1
case {d2}
V=V2
case {d3}
V=V3
end
Robert Cumming
Robert Cumming el 2 de Jul. de 2014
you need to use
==
for comparison, i.e.
if d1==max([d1,d2,d3)]
etc...

Categorías

Más información sobre Sparse Matrices en Centro de ayuda y File Exchange.

Preguntada:

el 2 de Jul. de 2014

Respondida:

el 2 de Jul. de 2014

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by