Find the work done for the force 𝐹⃗(x,y,z)= yz𝑖⃗ + xz 𝑗⃗ + (xy+2z) 𝑘⃗⃗ along the line segment from (1,0,-2) to (4,6,3)
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Chaitanya Yadav
el 14 de En. de 2022
Comentada: JANICE
el 28 de Nov. de 2023
Find the work done for the force 𝐹⃗(x,y,z)= yz𝑖⃗ + xz 𝑗⃗ + (xy+2z) 𝑘⃗⃗ along the line segment from (1,0,-2) to (4,6,3)
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Surya
el 21 de Nov. de 2023
clc
clear all
syms x y z t
f=input('Enter the components of 3D vector function [u,v,w] ');
r=input('Enter x,y,z in parametric form');
I=input('Enter the limits of integration for t in the form [a,b]');
a=I(1);b=I(2);
dr=diff(r,t);
F=subs(f,{x,y,z},r);
Fdr=sum(F.*dr);
I=int(Fdr,t,a,b)
P(x,y,z)=f(1);Q(x,y,z)=f(2); R(x,y,z)=f(3);
x1=linspace(0,1,10); y1=x1; z1=x1;
[X,Y,Z] = meshgrid(x1,y1,z1);
U=P(X,Y,Z); V=Q(X,Y,Z); W=R(X,Y,Z);
quiver3(X,Y,Z,U,V,W,1.5)
hold on
t1=linspace(0,1,10);
x=subs(r(1),t1);y=subs(r(2),t1);z=subs(r(3),t1);
plot3(x,y,z,'r')
2 comentarios
Raghav
el 27 de Nov. de 2023
Movida: DGM
el 28 de Nov. de 2023
clear
clc
syms x y z t
f=[y*z,x*z,x*y+2*z];
r=[3*t+1,6*t,5*t-2];
I=[0,1];
a=I(1);b=I(2);
dr=diff(r,t);
F=subs(f,{x,y,z},r);
Fdr=sum(F.*dr);
I=int(Fdr,t,a,b)
P(x,y,z)=f(1);Q(x,y,z)=f(2); R(x,y,z)=f(3);
x1=linspace(0,1,10); y1=x1; z1=x1;
[X,Y,Z]=meshgrid(x1,y1,z1);
U=P(X,Y,Z); V=Q(X,Y,Z); W=R(X,Y,Z);
quiver3(X,Y,Z,U,V,W,1.5)
hold on
t1=linspace(0,1,10);
x=subs(r(1),t1);y=subs(r(2),t1);z=subs(r(3),t1);
plot3(x1,y1,z1,'r')
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