Stacking order of figures

Suppose I create three figures
for ni = 1:3
figure
plot(rand(7))
drawnow
end
These will be drawn with Figure 1 on the bottom, Figure 2 in the middle, and Figure 3 on top, remaining viewable at the end.
How can change the stacking order? Prior to 2014b, one could sort the Children of the root object numerically, but I can't figure out how to do it in 2014b.

Respuestas (1)

Doug Hull
Doug Hull el 18 de Nov. de 2014

0 votos

Maybe I am misunderstanding the question:
close all
for ni = 1:3
figure
plot(rand(7))
drawnow
end
uistack(2,'top')
uistack(1,'top')

4 comentarios

the cyclist
the cyclist el 18 de Nov. de 2014
Editada: the cyclist el 18 de Nov. de 2014
You are not misunderstanding, but this tiny extension of your code does not correctly order the figures (in 2014b on latest Mac OS X):
rng('default')
NFIGURES = 4;
close all force
for nf = 1:NFIGURES
figure
plot(rand(7))
drawnow
end
for nf = NFIGURES-1:-1:1
uistack(nf,'top')
end
Bug?
FYI, how I did this formerly (and successfully) was
set(0,'Children',sort(get(0,'Children')));
matt dash
matt dash el 19 de Nov. de 2014
Have you tried
set(0,'Children',sort(double(get(0,'Children'))));
the cyclist
the cyclist el 19 de Nov. de 2014
Yes, that seems to work. Thanks!
men8th
men8th el 8 de Feb. de 2023
Editada: men8th el 8 de Feb. de 2023
An explicit version of the above command, which doesn't rely on casting a figure handle to double returning the figure number is:
set(groot,'Children',sort([get(groot,'Children').Number]))
This also uses groot to point to the graphics root object, rather than the magic number 0.
From reading the documentation, This will only find and re-order figures with visible handles. To work with all figures, you need to use findall.

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el 18 de Nov. de 2014

Editada:

el 8 de Feb. de 2023

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