I am adding two values together and it is rounding up but I don't need it to round up.

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material_cost = total * 3.67;
shipping_cost = total * 0.73;
total_cost = material_cost + shipping_cost;
fprintf('The material cost is $%0.2f. \n', material_cost);
fprintf('The shipping cost is $%0.2f. \n', shipping_cost);
fprintf('The total cost is $%0.2f. \n', total_cost);
so it prints out:
The material cost is $19.76.
The shipping cost is $3.93.
The total cost is $23.70.
the values are actually 19.7641, 3.9313, 23.6954 in the workspace.
How do I stop it from rounding the hidden numbers?

Accepted Answer

Image Analyst
Image Analyst on 16 Feb 2022
Use more decimal places of precision if you want. Instead of 2 with $%0.2f you can use 6 with $%0.6f.
DGM on 16 Feb 2022
Since it's not really clear which behavior you want, note that the behavior of floor() and fix() differ and may matter if you process negative inputs.

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More Answers (1)

DGM on 16 Feb 2022
Edited: DGM on 16 Feb 2022
If you simply want to truncate the values to integer cents, consider the example:
A = [19.7641, 3.9313, 23.6954]
A = 1×3
19.7641 3.9313 23.6954
B = truncatecents(A)
B = 1×3
19.7600 3.9300 23.6900
fprintf('before truncation: %.2f\n',A(3))
before truncation: 23.70
fprintf('after truncation: %.2f\n',B(3))
after truncation: 23.69
function out = truncatecents(in)
out = fix(in*100)/100; % truncate toward zero




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