How to 'flip/reverse' the signal?
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Hi all,
I have a signal like this (attached). This is sensor orientation data in z dimension during human walking.

I am extracting parts of the signal between red vertiical lines (precisely between first 8 and last 8 pairs of the lines).
When I plot all of them over one figure I get this.
hold on
for i = 1:length(S_or_z_cycle)
plot(S_or_z_cycle{i},'r') ;
title('Shank orientation Z'); xlabel('% of movement cycle'); ylabel('degrees')
end

Is there a way to "flip/reverse" the signal below 0 so it aligns with the signal above 0, remaining its shape? When I apply "-" I get this which is not what I want as it changes the shape of the signal.

Wheareas I want something like this:

1 comentario
Mathieu NOE
el 9 de Mzo. de 2022
Editada: Mathieu NOE
el 9 de Mzo. de 2022
hello Tomaszzz
seems you want to apply a vertical shift of the negative data so they overlay with the positive ones
this shift is computed by taking the mean of the negative curves minus the mean of the positive curves
Respuesta aceptada
Voss
el 11 de Mzo. de 2022
Editada: Voss
el 11 de Mzo. de 2022
load('data.mat')
hold on
for i = 1:length(S_or_z_cycle)
if mean(S_or_z_cycle{i}) > 0
plot(S_or_z_cycle{i},'r');
else
plot(S_or_z_cycle{i}+360,'r');
end
title('Shank orientation Z'); xlabel('% of movement cycle'); ylabel('degrees')
end
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