Avoiding for loop for 1d-intepolation
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Omid Sharifi Sedeh
el 21 de Mayo de 2022
Comentada: Omid Sharifi Sedeh
el 22 de Mayo de 2022
Hi,
Generally, I try to avoid for loops. Is there any way of avoiding the following for loop?
for ii=1:length(alpha)
result(ii) = interp1(Eng_mat,res(:,ii),alpha(ii),'linear', 'extrap');
end
Dimension of the matrices: Eng_mat is 4000*1, res is 4000*10, alpha is 10*1
In principle, I need to use interpolation for each element of alpha according to ii'th coloumn of res.
I appreciate it if someone could help me with this.
Thanks
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Image Analyst
el 21 de Mayo de 2022
I don't see a simpler way off the top of my head. You have only 10 iterations so I wouldn't worry about it. Ten iterations of a for loop will probably be faster than any other way you'd do it. If you had tens of millions of iterations then maybe it would be time to worry about a for loop, but for 10? Don't worry about it.
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Image Analyst
el 22 de Mayo de 2022
Over a million times? How do you get that from this:
"Dimension of the matrices: Eng_mat is 4000*1, res is 4000*10, alpha is 10*1"
Your loop is over alpha which has only 10 values.
Look, here is a loop that iterates a million times:
tic
for k = 1 : 1000
;
end
toc
Elapsed time is 0.000454 seconds.
So on my 10 year old computer a million iterations takes less than half a millisecond. So it's not the for loop itself that's taking up all the time. It's whatever you do inside of it.
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