How to Plot scatterplot in Single loop in App designer

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Med Future
Med Future el 16 de Jun. de 2022
Comentada: Geoff Hayes el 1 de Jul. de 2022
Hello Everyone, I have 8 scatter plot, currently i am ploting it manually in app designer, i want to plot it in loop , the loop value start from 1:8
I have the following code.How can i modified it as for loop.
when we make for loop clusters{1} become clusters{i},
but main error in app.UIAxes_10
scatter(app.UIAxes_10,clusters{1}(:,1),clusters{1}(:,2))
scatter(app.UIAxes_11,clusters{2}(:,1),clusters{2}(:,2))
scatter(app.UIAxes_12,clusters{3}(:,1),clusters{3}(:,2))
scatter(app.UIAxes_13,clusters{4}(:,1),clusters{4}(:,2))
scatter(app.UIAxes_14,clusters{5}(:,1),clusters{5}(:,2))
scatter(app.UIAxes_15,clusters{6}(:,1),clusters{6}(:,2))
scatter(app.UIAxes_16,clusters{7}(:,1),clusters{7}(:,2))
scatter(app.UIAxes_17,clusters{8}(:,1),clusters{8}(:,2))
Loop code i tried
for i = 1:8
scatter(app.UIAxes_(i),clusters{i}(:,1),clusters{i}(:,2))
end

Respuestas (1)

Geoff Hayes
Geoff Hayes el 16 de Jun. de 2022
@Med Future - if you create an array of your axes, then you will be able to loop over it. Something like the following might work
axesArray = {app.UIAxes_10, app.UIAxes_11, app.UIAxes_12, app.UIAxes_13, app.UIAxes_14, app.UIAxes_15, app.UIAxes_16, app.UIAxes_17};
for i = 1:8
scatter(axesArray{i},clusters{i}(:,1),clusters{i}(:,2))
end
  6 comentarios
Stephen john
Stephen john el 1 de Jul. de 2022
@Geoff Hayes Its no working. beacuse it does not plot app.NoClusterLabel_2 this one does not go to the loop
Geoff Hayes
Geoff Hayes el 1 de Jul. de 2022
@Stephen john - please show your code and describe what is going wrong.

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