How do I compare two shuffled vectors, and get the indexes of one as it appears in the other?

I have two vectors of strings, one is a shuffled version of the other. I want to get a new vector that has the indexes of the elements in the first vector, as they appear in the second.

So, for example, for the following two vectors:

A=["cond1","cond2","cond3","cond4"];
b=["cond4","cond2","cond1","cond3"];

I'd want to get the following output

ans = 3 2 4 1

I.e. telling me that the first element in A is in position 3 in B, the second is in position 2, and so on.

[Stephen23]

"I have two vectors of strings,"

But what you showed us are character vectors. Because square brackets are a concatenation operator, your example data:

A = ['cond1','cond2','cond3','cond4'];

is exactly equivalent to this:

A = 'cond1cond2cond3cond4';

Perhaps you really meant to show us string arrays, not the character arrays that you actually gave us.

[Henry Brice]

Thanks, sorry, corrected.

Answer 1

[Stephen23]

A = ["cond1","cond2","cond3","cond4"];
b = ["cond4","cond2","cond1","cond3"];
[~,X] = ismember(A,b)

X = 1×4

3 2 4 1

Answer 2

[David Hill]

 b=["cond4","cond2","cond1","cond3"];%needs to be string array
 [~,idx]=sort(b)

idx = 1×4

3 2 4 1