How to produce a matrix with the following conditions?

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M
M el 13 de Sept. de 2022
Respondida: Walter Roberson el 15 de Sept. de 2022
How to produce a matrix which size is 7*7 and contains all possible single locations of a certain value and the rest of the column's values are 1. For example : The value is 0.4 and I want to produce seven columns of different single locations of 0.4 and the other values are 1 such as: [0.4 1 1 1 1 1 1; 1 0.4 1 1 1 1 1; 1 1 0.4 1 1 1 1; 1 1 1 0.4 1 1 1; 1 1 1 1 0.4 1 1; 1 1 1 1 1 0.4 1; 1 1 1 1 1 1 0.4]

Respuesta aceptada

Sam Chak
Sam Chak el 13 de Sept. de 2022
Hi @M
Maybe like this?
M = ones(7)
M = 7×7
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
I = eye(7)
I = 7×7
1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 1
v = 0.4;
u = repelem(v, 7)
u = 1×7
0.4000 0.4000 0.4000 0.4000 0.4000 0.4000 0.4000
D = diag(u)
D = 7×7
0.4000 0 0 0 0 0 0 0 0.4000 0 0 0 0 0 0 0 0.4000 0 0 0 0 0 0 0 0.4000 0 0 0 0 0 0 0 0.4000 0 0 0 0 0 0 0 0.4000 0 0 0 0 0 0 0 0.4000
Solution = M - I + D
Solution = 7×7
0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000
  2 comentarios
Les Beckham
Les Beckham el 13 de Sept. de 2022
Or, with a few less steps:
M = ones(7);
M(logical(eye(7))) = 0.4
M = 7×7
0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000
Sam Chak
Sam Chak el 13 de Sept. de 2022
Hi @Les Beckham, thanks for introducing the logical approach. 👍

Iniciar sesión para comentar.

Más respuestas (1)

Walter Roberson
Walter Roberson el 15 de Sept. de 2022
M = ones(7);
C = M;
C(logical(eye(7))) = 0.4
C = 7×7
0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000
%or
M = ones(7);
C = M;
C(1:size(C,1)+1:end) = 0.4
C = 7×7
0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000
%or
M = ones(7);
C = M - 0.6 * eye(size(M))
C = 7×7
0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000

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