How to remove a part of a character?

Hi all,

Suppose that I have a character called Date='1938-03-01'. I want to remove the year part(1983). 1983 is just an example. I want to remove any year form the date. How can I do that?

Answer 1

[Voss]

Date = '1938-03-01';
Date(1:4) = []

Date = '-03-01'