# How to solve equation by linearisation - Picard/Newton Raphson?

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T el 16 de En. de 2023
Editada: Torsten el 17 de En. de 2023
Hi,
I want to solve this equation
1/(1/b + x*(1/a - 1/b)) - 1/(10/b + y*(10/a - 10/b)) = 0
where a and b are constants.
My question is on how can I write this in matrix form and solve over iterations.
I want to write it as [ ] [ x; y] = [ ]
May be linearisation / NR/Picard etc. might help but I am clueless how to proceed.
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Torsten el 17 de En. de 2023
Editada: Torsten el 17 de En. de 2023
I'm clueless why you want to write the equation as
[ ] [ x; y] = [ ]
Can you give a plausible reason ?
And what do you mean by "solve" ? You have one equation in two unknowns. So solving in the usual sense would mean: writing x as a function of y (or vice versa).

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