How to solve equation by linearisation - Picard/Newton Raphson?
2 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Hi,
I want to solve this equation
1/(1/b + x*(1/a - 1/b)) - 1/(10/b + y*(10/a - 10/b)) = 0
where a and b are constants.
My question is on how can I write this in matrix form and solve over iterations.
I want to write it as [ ] [ x; y] = [ ]
May be linearisation / NR/Picard etc. might help but I am clueless how to proceed.
Could you please help?
1 comentario
Torsten
el 17 de En. de 2023
Editada: Torsten
el 17 de En. de 2023
I'm clueless why you want to write the equation as
[ ] [ x; y] = [ ]
Can you give a plausible reason ?
And what do you mean by "solve" ? You have one equation in two unknowns. So solving in the usual sense would mean: writing x as a function of y (or vice versa).
Respuestas (0)
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!