Multiply and integrate two plots for single output value

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Ben Bawtree
Ben Bawtree el 27 de Mzo. de 2023
Respondida: Peter Perkins el 27 de Mzo. de 2023
Below is illustrated the code used to compute functions, with a comment at the bottom summarising the aim. To obtain a single value for annual energy output from two plots.
%% Clear Workspace
clc; clear all; clear;
% Define Parameters
K_0 = 3149/1080;
K_1 = 469/1080;
T_1 = 12.4/24; %hours
T_0 = 353/24; %hours
% Define Timestep
ts_min = 2; %mins
ts_hours = ts_min/60;
ts_days = ts_hours/24;
ts_years = ts_days/365;
start_val = 0; % days
end_val = 365; % days
nElements = 1/ts_years; % intervals in a year
ts = linspace(start_val, end_val, nElements); % create timestep array
% Define Harmonic Analysis
V = (K_0 + K_1.*cos((2.*pi.*ts)/T_1)).*cos((2.*pi.*ts)/T_0);
V2 = V.^2;
Vnorm = sqrt(V2);
grid on;
% Plot Histogram of Wind Velocity Frequencies
grid on;
%% Tidal Power Curves for 4m and 6.5m from Excel
PowerTable = readtable('TidalData.xlsx','Sheet','Sheet1');
x4 = PowerTable.Header1; % Flow Speed [m/s] at 4m turbine
y4 = PowerTable.Header2; % Electrical Power [kW] at 4m turbine
x63 = PowerTable.Header3; %: Flow Speed [m/s] at 6.3m turbine
y63 = PowerTable.Header4; %: Electrical Power [kW] at 6.3m turbine
hold on;
grid on;
hold off;
%% Multiplication Calculation power curve by yearly quantity
% aim to multiply plot(x4,y4)- flow speed (m/s) vs. electrical power (kW),
% by hist(Vnorm)- flow speed (m/s) vs. annual number of hours, to get the total annual
% electrical power kWh in a year..
  4 comentarios
Ben Bawtree
Ben Bawtree el 27 de Mzo. de 2023
Understood thank you, will attempt this.

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Respuestas (1)

Peter Perkins
Peter Perkins el 27 de Mzo. de 2023
Any time the number 365 appears in code, thatr's probably a bug.
You might try to use datetimes and durations in your code, including the plot.


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