Transform double to char with one or two decimal places

I have a series of numbers:

n_A = 3.15;
n_B = 3.7;

I have to transform them into char considering 1 or 2 decimal digits based on the starting number, i.e. like this:

n_A = 3.15;    
A = sprintf('%.2f',n_A);

n_B = 3.7;    
B = sprintf('%.1f',n_B);

My question is how can I apply this:

sprintf('%.2f',#);

or this:

sprintf('%.1f',#);

knowing that the number has one or two digits after the decimal point?

Answer 1

[Stephen23]

You could use another format, e.g.:

fprintf('%.3g\n',[3.15,3.7])

3.15
3.7

[Alberto Acri]

Thanks for your answer @Stephen23. The one above is an example.

If I have a number (double) in input (n_A or n_B for example) I want in output a char number that has one or two decimal digits based on the input number.

So,

• if N = 3.15 this becomes '3.15' (char)
• if N = 3.70 this becomes '3.7' (char).

[Walter Roberson]

n_A = 3.15;
fprintf('%g\n', n_A);

3.15

n_B = 3.70;
fprintf('%g\n', n_B)

3.7

format long g
n_A

n_A = 
                      3.15

n_B

n_B = 
                       3.7