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Problem-based optimization: Initial guess for only one variable

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b999
b999 el 25 de Oct. de 2023
Comentada: Walter Roberson el 26 de Oct. de 2023
Hello,
I have a optimization problem with the problem-based approach and I am defining a few variables
A = ones(50,10);
a = optimvar("a",size(A),"Type","integer","LowerBound",0,"UpperBound",2);
b = optimvar("b",size(a),"Type","integer","LowerBound",0,"UpperBound",2);
c = optimvar("c",size(a),"Type","integer","LowerBound",0,"UpperBound",2);
Now I want to make an initial guess for only a, because I can't guess values for b and c. I tried it like this, but it doesn't work:
initial_guess = ...;
x0 = struct('a', initial_guess, 'b', [], 'c', []);
...
solution = solve(prob, x0);
It says, that b and c can't be empty. But I don't know how to implemnt it in another way.
Is there a possibilty to make a guess for only one variable?
(If I am defining b and c e.g. as zeros, the guess is infeasable)
  2 comentarios
Fabio Freschi
Fabio Freschi el 25 de Oct. de 2023
Why don't you set your b and c variables in the middle of the range? In your case 1?
b999
b999 el 25 de Oct. de 2023
Because I have a lot of constraints besides the variables, which are not fulfilled then.

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Respuestas (1)

Walter Roberson
Walter Roberson el 25 de Oct. de 2023
there are only 3^3 different possibilities. Run them each in turn hardcoding one particular a, b, c possibility. Take the best of the 27 results as the solution.
  2 comentarios
b999
b999 el 25 de Oct. de 2023
It is an easy example to show my problem. The Size of the Variables could be 50x10 or more and there are more than three variables. The a,b and c is just an example. I can't try taht many possibilities
Walter Roberson
Walter Roberson el 26 de Oct. de 2023
Is there a possibilty to make a guess for only one variable?
NO.

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