fftshift implementation in Simulink

2 visualizaciones (últimos 30 días)
Hamza
Hamza el 23 de En. de 2025
Comentada: Paul el 24 de En. de 2025
I need to generate IPs for HDL implementation of an algorithm. I need to do fftshift in simulink but there is no fftshift block avaiable. Is there any way we can do fftshift of the output data from FFT block from DSP HDL toolbox? I am attaching FFT model for reference.

Respuesta aceptada

Walter Roberson
Walter Roberson el 23 de En. de 2025
Fork the fft output. Use https://www.mathworks.com/help/dsp/ref/variableselector.html variable selector block on each of the branches, with Fixed selector. In one of the branches select 1:floor(signal_length)/2 and in the other branch select floor(signal_length)/2+1:signal_length . Now concatenate those two together in reverse order.
This potentially requires hard-coding the signal length.
  3 comentarios
Walter Roberson
Walter Roberson el 24 de En. de 2025
good point
x = 1:9;
signal_length = numel(x);
fftshift(x)
ans = 1×9
6 7 8 9 1 2 3 4 5
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
[x(ceil(signal_length/2)+1:signal_length), x(1:ceil(signal_length/2))]
ans = 1×9
6 7 8 9 1 2 3 4 5
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
Paul
Paul el 24 de En. de 2025
I just realized that this block requires the FFT length to be a power of 2, so the ceil() isn't necessary for this particular use case.

Iniciar sesión para comentar.

Más respuestas (1)

Paul
Paul el 23 de En. de 2025
Editada: Paul el 23 de En. de 2025
fftshift is extended to code generation. Assuming the data output from the FFT block is in linear order, you can call fftshift from inside a MatlabFunction block.

Etiquetas

Productos


Versión

R2023b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by