How do I post a picture with my question
Mostrar comentarios más antiguos
How can I add this image?
1 comentario
Walter Roberson
el 10 de Jun. de 2011
See also this partial list of sites you can upload your picture to:
http://www.mathworks.com/matlabcentral/answers/7924-where-can-i-upload-images-and-files-for-use-on-matlab-answers
Respuesta aceptada
Más respuestas (4)
Doug Hull
el 21 de En. de 2011
2 votos
Daniel Shub
el 17 de Mayo de 2012
0 votos
If someone posts a question with a link like http://tinypic.com/r/14bib77/6 and I want to edit the question to embed the image I get

and that looks really ugly. Is there anything I can do besides re-uploading the image?
7 comentarios
Walter Roberson
el 17 de Mayo de 2012
Unfortunately no.
Part of the problem is the image size: the Answers site makes no attempt to resize the images to fit the reader's screen.
Jan
el 20 de Mayo de 2012
Ask the author to create a cropped version of the image.
Walter Roberson
el 21 de Mayo de 2012
In the case of tinypic, you can right-click on the preview image and copy the URL of the preview.
Daniel Shub
el 21 de Mayo de 2012
@Jan, I might be being pessimistic, but I think that is a losing battle.
@Walter, but the preview, at least in this case, has the padding also.
Jan
el 21 de Mayo de 2012
@Daniel: You can download the image, crop it with the IPT or even in pure Matlab, save it a tinypic again and change the link in the original question. Well, of course the OP could do this also.
Finally I write this only to confirm, that this is a losing battle. Sigh.
Walter Roberson
el 21 de Mayo de 2012
I embedded that _exact_ preview, in a Question a day or so, and had no difficulty with it being off the right hand side.
Daniel Shub
el 22 de Mayo de 2012
@Walter, you tried to embed the "exact preview" but you didn't. The question is here:
http://www.mathworks.com/matlabcentral/answers/38620-processing-image-with-deconvolution
Basically there are two images: http://tinypic.com/r/2u95qwg/6 and http://tinypic.com/r/14bib77/6 You embedded the 2u95qwg image twice. If I embed that image it works for me also. The 14bib77 image does not work.
Jan
el 21 de Sept. de 2013
0 votos
Now pictures can be uploaded directly in the forum, see: http://www.mathworks.com/matlabcentral/answers/87583#answer_97176Y . A great step to improve the usability of the forum!
Hamad Abdin
el 31 de Oct. de 2020
0 votos
function [root, fx, es, iter] = modsecantmeth(func, xr, es, del, maxit)
% modsecantmeth: root location
% [root, es, iter] = modsecantmeth(func, xr, es, del maxit:
% uses Modified Secant Method to find roots of func
% input:
% func = name of function
% xr = initial guess
% es = desired relative error ( default = 0.0001%)
% del = perturbation fraction (default = 1e-6)
% output
% root = real root
% ea = approximate relative error (%)
% iter = number of iterations
% operational notes
% none.
if nargin < 2, error('at least 2 input arguments required'),end
if nargin < 3 || isempty(es), es = 0.0001;end
if nargin < 4 || isempty(del), del = 1e-6;end
if nargin < 5 || isempty(maxit), maxit = 50;end
iter = 0;
ea = 100;
while (1)
xrold = xr;
xr =xr - del *xr*func(xr)/(func(xr+(del*xr))-func(xr));
iter = iter +1;
if xr~= 0, ea = abs((xr-xrold)/xr)*100;end
data(:,iter) = [iter, xrold, xr, ea];
if ea <= es || iter >= maxit, break, end
end
root = xr; fx = func(xr);
disp('Secant Method Results')
disp('iter, old xr, new xr, |ea|')
disp('data')
2 comentarios
Hamad Abdin
el 31 de Oct. de 2020
can you help me to make run.
Rik
el 31 de Oct. de 2020
This is completely unrelated to this question. Read this https://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer
After that, post this as your own question (don't forget to have a proper layout of your post, see this link: https://www.mathworks.com/matlabcentral/answers/help/rtc#rtc_summary )
This answer will be deleted shortly.
Categorías
Más información sobre Historical Contests en Centro de ayuda y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
