need a matlab program please

i have a random binary matrix...... say a coloumn matrix

h= [1 1 1 0 0 0 0 0 1 0 0 1 1 0 0 1]';

i need to find the weightage of 0's and 1's.. like i need an answer like [(3,1); (5,0); (1,1); (2,0); (2,1); (2,0); (1,1)].. can u help me to get my answer in this form?

the answer matrix shows the number of 1's and 0's ... please help me to solve this problem.....

[Walter Roberson]

That would normally be referred to as "run length encoding". And it is clearly a homework assignment. As what have you come up with? http://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer

Answer 1

[Star Strider]

One approach:

h= [1 1 1 0 0 0 0 0 1 0 0 1 1 0 0 1]';
dh = diff([0; h; 0]);                           % Differences To Detect Start, End Of Consecutive [1,0]
hi = find(dh>0);
lo = find(dh<0);
Result = diff(sort([hi; lo]))                   % Sort & Take Differences

Result =
     3
     5
     1
     2
     2
     2
     1

[krishan goyal]

thank you so much for ur answer...

[krishan goyal]

but what if i want to display my answer like [(3,1); (5,0); (1,1); (2,0); (2,1); (2,0); (1,1)].. can u help me to get my answer in this form?

[Star Strider]

It only requires a simple change.

The updated code:

h= [1 1 1 0 0 0 0 0 1 0 0 1 1 0 0 1]';
dh = diff([0; h; 0]);                           % Differences To Detect Start, End Of Consecutive [1,0]
hi = find(dh>0);
lo = find(dh<0);
srthilo = sort([hi; lo]);                       % Sort
runs = diff(sort([hi; lo]));                    % Take Differences
Result = [runs h(srthilo(1:length(runs)))]

       3     1
       5     0
       1     1
       2     0
       2     1
       2     0
       1     1

Answer 2

[Walter Roberson]

diff(find(diff([~h(1); h; ~h(end)])~=0))

for labeling, h(1) is the first label and the rest will always alternate between 0 and 1. Odd numbered positions will be h(1) and even numbered positions will be ~h(1)

[krishan goyal]

but what if i want to display my answer like [(3,1); (5,0); (1,1); (2,0); (2,1); (2,0); (1,1)].. can u help me to get my answer in this form?

[Walter Roberson]

I already did help you about that. I pointed out how to determine the labels. The rest of it is string formatting, unless you are willing to settle for a 2D matrix [3, 1; 5, 0; 1, 1; 2, 0; 2, 1; 2, 0; 1, 1] in which case it is very easy.

Answer 3

[Jacky Jo]

If you like the long coding:

    A= [1 1 1 0 0 0 0 0 1 0 0 1 1 0 0 1]';
len=length(A);
A(len+1,1)=NaN; 
Count_1=0;    Count_0=0;
Pos=0;
for i=1:len
    fprintf('\t%d',i)
    if A(i,1)==1         
        Count_1=Count_1+1;        
        if  A(i,1)>A(i+1,1)
            Pos=Pos+1
            B(Pos,1)=Count_1;
            Count_1=0;
        elseif i==len 
            Pos=Pos+1
            B(Pos,1)=Count_1;
            Count_1=0;
        end
    elseif A(i,1)==0
        Count_0=Count_0+1;       
        if A(i,1)<A(i+1,1)
            Pos=Pos+1
            B(Pos,1)=Count_0;
            Count_0=0;
        elseif i==len 
            Pos=Pos+1
            B(Pos,1)=Count_1;
            Count_1=0;
        end
    end
end
fprintf('The weightage of 0s and 1s:\n');
disp(B);