image processing- calculate image blur extend and direction
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The code was
c(i)=fft(log(abs(image)));
then calculate c(i') to get the calculate image blur extend and direction. for differentiation of the image i am used sobel filter.bt the diagram(answer) i got was not relevant... i dont know where the mistke? whether using fft or fft2 or fftn for images? or which filter is appropriate for use?
[Merged from duplicate question]
i want to process the image. for the image i have to calculate fft, then abs,then log,t hen again fft. during calculating abs the output was simply white screen. no original image? whats the reason?
6 comentarios
christian bale
el 13 de En. de 2012
can u be clear with ur question so i can help u
Walter Roberson
el 13 de En. de 2012
You should probably be using fft2() for images.
munch kitty
el 19 de En. de 2012
Walter Roberson
el 19 de En. de 2012
Umm, IEEE has published at least 4 different papers.
munch kitty
el 19 de En. de 2012
Walter Roberson
el 19 de En. de 2012
You wrote, "actually in the ieee paper" and I am pointing out that IEEE has published multiple papers -- in other words we do not know WHICH paper you are looking at.
Respuestas (2)
christian bale
el 19 de En. de 2012
1 voto
manoj kitty try in scilab it would be easy than matlab
6 comentarios
Ganesh
el 19 de En. de 2012
Hi manoj!!!!!!How many members in ur project?
munch kitty
el 20 de En. de 2012
Ganesh
el 20 de En. de 2012
How'd u divide ur project module among with ur project members?
munch kitty
el 20 de En. de 2012
Ganesh
el 20 de En. de 2012
Am from bangalore man...working in DIIP analyst.
Ganesh
el 20 de En. de 2012
Just wanna know so far what u ve implemented in project thats y i asked how many members..
Walter Roberson
el 19 de En. de 2012
0 votos
What datatype are you using for your image? If it was an image file that was read in using imread() then the datatype is probably uint8, unsigned 8 bit integers, in which case abs() would not have any effect.
7 comentarios
munch kitty
el 19 de En. de 2012
Walter Roberson
el 19 de En. de 2012
Well, abs() of an unsigned value is just going to be the same value, so you could skip the abs.
But to double-check: are you sure it was not fft(abs(log(image))) with the abs() applied to the log() ?
Walter Roberson
el 19 de En. de 2012
class() will tell you which datatype something is. double, uint8, uint16, and so on.
munch kitty
el 20 de En. de 2012
Walter Roberson
el 20 de En. de 2012
I seem to have missed you showing us the class() of your image.
In your other active thread, you have fft(log(abs(fft(image)))) with an fft() as the lowest level operation. It makes sense to abs() the result of fft, whereas it does not make sense to abs() the image directly.
munch kitty
el 20 de En. de 2012
Walter Roberson
el 20 de En. de 2012
I glanced at the description a number of months ago, but I did not see the point of it at that time, so I am not likely to be able to describe how to use it.
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