How to replace any value into vector or matrix to -inf

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Triveni
Triveni el 12 de Jul. de 2016
Comentada: Walter Roberson el 12 de Jul. de 2016
ab =
11.0000
11.5000
12.0000
12.1000
12.2000
12.3000
11.2000
9.0000
9.5000
11.3000
ab<10
ans =
Columns 1 through 9
0 0 0 0 0 0 0 1 1
Column 10
0
ab1
ab1 =
Columns 1 through 5
11.0000 11.5000 12.0000 12.1000 12.2000
11.1000 11.4000 12.0000 12.1000 12.2000
Columns 6 through 10
12.3000 11.2000 9.0000 9.5000 11.3000
12.3000 11.2000 9.0000 9.5000 11.3000
>> ab1<10
ans =
Columns 1 through 9
0 0 0 0 0 0 0 1 1
0 0 0 0 0 0 0 1 1
Column 10
0
0
i want to replace ab<10 to -inf, without loop, and other variables and matrix size remains same. It should be applicable to any type of matrix.

Respuesta aceptada

Walter Roberson
Walter Roberson el 12 de Jul. de 2016
ab(ab<10) = -inf;
  2 comentarios
Triveni
Triveni el 12 de Jul. de 2016
Editada: Walter Roberson el 12 de Jul. de 2016
Sir, If i need to be make other matrix's index -inf then how can i do?.
f_data =
1.0000
13.5000
11.0000
12.1000
12.2000
13.3000
11.2000
13.0000
13.5000
8.3000
In both matrices any index<10, i have to make both corresponding matrix -inf.
Walter Roberson
Walter Roberson el 12 de Jul. de 2016
mask = ab<10 | f_data<10;
a(mask) = -inf;
f_data(mask) = -inf;

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