Alternate for flipr command in matlab

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Bathrinath
Bathrinath el 1 de Mzo. de 2012
Hi,
m = 3; n = 8; There are 8 elements in A
A = [33,47,44,49,40,21,45,48];
After sorting in descending order
A = [49,48,47,45,44,40,33,21]
I need final matrix
final =[ 49 48 47 ; 40 44 45 ; 33 21 ]
In first two rows 3 elemets has to be there.
In third row 2 elements has to be there,because n = 8.
Second row is printed in reverse order.
I cant use "flipr" in this case bcoz matrix is not same size.
Alternate rows has to be printed in reverse order.
Advice me regarding this.

Respuestas (2)

Walter Roberson
Walter Roberson el 1 de Mzo. de 2012
You cannot create a numeric matrix which has different number of elements in various rows or columns. 8 elements cannot be arranged in to a 3-row numeric matrix -- not without adding an extra element.

Andrei Bobrov
Andrei Bobrov el 1 de Mzo. de 2012
A = [33,47,44,49,40,21,45,48];
m = 3;
n = numel(A);
out = nan(m,ceil(n/m));
out(1:n) = sort(A,'descend');
out(:,2:2:end) = out(end:-1:1,2:2:end);
out = out'

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