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how to find index of a cell that contains a numeric value?

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Terek Li
Terek Li on 17 Oct 2016
Commented: Adam on 17 Oct 2016
Hi, there are several posts regarding this question, but none of their solutions actually work...
I have a 1000*1 cell containing random double values, how do I find the index of the cell that contains a specific value x?
I tried to do this:
index = find([data(:,1)] == x)
but I get an error saying: Undefined operator '==' for input arguments of type 'cell'.
Please help, thank you!

  1 Comment

Guillaume
Guillaume on 17 Oct 2016
Any reason you're using a cell array for storing scalar values? Using a matrix would be a lot simpler since the above code would then work (and matrices are a lot more memory efficient).

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Accepted Answer

Adam
Adam on 17 Oct 2016
find( cellfun( @(d) isequal( d, x ), data) );
works theoretically, but you should never be testing for exact equality with doubles if they are not integer-valued. You should instead replace isequal(...) with some function of your own that uses a tolerance for comparison.

  2 Comments

Adam
Adam on 17 Oct 2016
It's not a matter of efficiency it is a matter of the level of accuracy with which a value can be represented in a double. Floating point values cannot be 100% accurately represented so what should be the same value, being arrived at by two different mathematical processes can be represented slightly differently - e.g. 1e-10 different from each other, something that as far as makes no difference is equal to us as humans, but will fail an equality test.
You can read up on this anywhere on the internet related to floating point accuracy if you want.

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