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User-defined function help

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Elizabeth Jurgensen
Elizabeth Jurgensen el 4 de Mzo. de 2018
Comentada: Prajith Chilummula el 12 de Mzo. de 2018
function [Temp] = TempProfile(r)
%UNTITLED9 Summary of this function goes here
% Detailed explanation goes here
Temp = 1500-(((9.61*10e26)*r.^2)/(4*0.05));
end
I have the function above. I am trying to display the Temp for the value of r; r = 0:0.41 How would I display all the values of Temp for all the values of r? Where would I define r as 0:0.41? Thank you so much!
  2 comentarios
Walter Roberson
Walter Roberson el 4 de Mzo. de 2018
There are approximately 2^59 representable numbers in the range 0 to 0.41. You do not have have enough memory to store all of the calculations and calculating them all would take many centuries.
I recommend that you reconsider displaying all of those values. Perhaps you do not need more than (say) 1000000000000 of the values in that range.
Prajith Chilummula
Prajith Chilummula el 12 de Mzo. de 2018
Consider the number of values you want to use between 0 and 0.41 and modify the increment step likely.Then you can pass the vector as argument and get the output temp array.You can plot the arrays.
Example:
r=0:0.1:0.41;
temp=TempProfile(r);
plot(r,temp);

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