What does this error mean?

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Evan Mossel
Evan Mossel el 23 de Jul. de 2018
Editada: Evan Mossel el 26 de Jul. de 2018
I keep getting the error: Subscript indices must either be real positive integers or logicals.
days=10;
dy=-1;
hPlot1 = plot(dy,alt);
while dy<=days
%--calculate & display current time (UTC)
yr=2018;
mnth=1;
dy=dy+1;
hr=0;
min=0;
sc=0;
d=datetime(yr,mnth,dy,hr,min,sc);
%d=datetime('now');
%--covert and display current time in julian days
JD_TT=juliandate(d);
%--convert julian days to moon position
CooType='q2000';
[X,Y,Z]=moonpos(JD_TT,CooType);
%plot3(X,Y,Z);
%--convert to LLA coordinates, in degrees
alt=sqrt(X.^2+Y.^2+Z.^2);
xdata = get(hPlot1,'XData');
ydata = get(hPlot1,'YData');
set(hPlot1,'XData',[xdata dy],'YData',[ydata alt]);
end
altmax=max(ydata);
xmax=find(alt==altmax);
altmin=min(ydata);
xmin=find(alt==altmin);
  15 comentarios
Walter Roberson
Walter Roberson el 24 de Jul. de 2018
Your xdata and ydata is going to include that initial nan value.
At the end of your loop, your xdata and ydata are not going to include the last dy and alt, because you change hPolt1's XData and YData after you assign to the temporary variable xdata and ydata.
Evan Mossel
Evan Mossel el 26 de Jul. de 2018
Editada: Evan Mossel el 26 de Jul. de 2018
I changed the xdata/ydata to Xdata/Ydata but this did not resolve the issue.
Update: I misunderstood. This fixed the issue

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Respuestas (1)

Krithika A
Krithika A el 24 de Jul. de 2018
You use min in your code. min is already a matlab function
  5 comentarios
Krithika A
Krithika A el 24 de Jul. de 2018
Not specifically for min/max. Min/max can handle non-integers. It would be another function.
Evan Mossel
Evan Mossel el 24 de Jul. de 2018
I believe it is the 'find' function. I will try to work it out.

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