# elimination of consecutive regions

2 views (last 30 days)
Michal on 27 Sep 2018
Commented: Michal on 29 Sep 2018
I need to effectively eliminate consecutive regions in vector "a" or better in rows/columns of matrix "A" with length of separate ones regions greater than positive integer N <= length(A):
See following example:
N = 2 % separate consecutive regions with length > 2 are zeroed
a = [0 1 1 0 0 1 1 1 0 0 1 1 1 1 0 1]
a_elim = [0 1 1 0 0 0 0 0 0 0 0 0 0 0 0 1]
or 2D case:
N = 2
A = [1 0 1
1 1 0
1 1 0
0 0 1
1 1 1]
% elimination over columns
A_elim= 0 0 1
0 1 0
0 1 0
0 0 1
1 1 1
% elimination over rows
A_elim= 1 0 1
1 1 0
1 1 0
0 0 1
0 0 0
I am looking for effective vectorized function performing this task for size(A) ~ [100000, 1000] (over columns case).

Matt J on 27 Sep 2018
Edited: Matt J on 27 Sep 2018
e=ones(N+1,1);
end
Michal on 29 Sep 2018
Hi Matt … now your solution works very well. Is faster and significantly less memory consuming than Bruno's code. Moreover, the "mask" is very useful to know.
Thanks!!!

Bruno Luong on 27 Sep 2018
Edited: Bruno Luong on 27 Sep 2018
You could use Huffman encoding (there might be some on the FEX), but the idea is similar to this direct code:
N = 2
A = [1 0 1;
1 1 0;
1 1 0;
0 0 1;
1 1 1];
% Engine for working along the column (1st dimension)
[m,n] = size(A);
z = zeros(1,n);
[i1,j1] = find(d==1);
[i0,j0] = find(d==-1);
lgt = i0-i1;
keep1 = lgt <= N;
keep0 = keep1 & i0 <= m;
i1 = [i1,j1];
i0 = [i0,j0];
C1 = accumarray(i1(keep1,:),1,[m n]);
C0 = accumarray(i0(keep0,:),-1,[m n]);
Aclean = cumsum(C1+C0,1);
Aclean
If you want to filter along the 2nd dimension, transpose A, apply the above, then transpose the result Aclean.
Michal on 27 Sep 2018
Yes, you are right, the pure MATLAB Huffman encoding is not quite fast. I will test all options. Anyway, your code looks as very good method.
Thanks!

Michal on 27 Sep 2018
Edited: Michal on 27 Sep 2018
good idea (only 1D) is here

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