How to avoid intersection of node in WSN node deployment.

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ALA SHARAF
ALA SHARAF el 6 de Feb. de 2019
Comentada: ALA SHARAF el 6 de Feb. de 2019
I have created a WSN scenario and node deployment.But in real world no two WSN nodes can be in same position.how to avoid intersection of nodes.the code used for node deployment is given below.
for i = 1:numNode
% x coordination of node
nodeArch.node(i).x = rand * netArch.Yard.Length;
nodeArch.nodesLoc(i, 1) = nodeArch.node(i).x;
% y coordination of node
nodeArch.node(i).y = rand * netArch.Yard.Width;
nodeArch.nodesLoc(i, 2) = nodeArch.node(i).y;
% the flag which determines the value of the indicator function? Ci(t)
nodeArch.node(i).G = 0;
% initially there are no cluster heads, only nodes
nodeArch.node(i).type = 'N'; % 'N' = node (nun-CH)
nodeArch.node(i).energy = netArch.Energy.init;
nodeArch.node(i).CH = -1; % number of its CH ?
nodeArch.dead(i) = 0; % the node is alive
end

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KSSV
KSSV el 6 de Feb. de 2019
Get the distance between the picked points and other points, you may use knnsearch or pdist, pdist2......if the distance is zero (or some tolerance) then the points are same.....as you know the indices..you can discard those points.
  3 comentarios
KSSV
KSSV el 6 de Feb. de 2019
Editada: KSSV el 6 de Feb. de 2019
I have already mentioned it....you can fix your tolerance value.

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