Saving all output of for loop
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Tchilabalo
el 12 de Mayo de 2019
Comentada: madhan ravi
el 16 de Mayo de 2019
for i=1:1500
X1=J(i)-sqrt((D(i)^2)/((sqrt(A(i))+1)))
Y1=I(i)-A(i)*(J(i)-X1)
X2=J(i)+sqrt((D(i)^2)/((sqrt(A(i))+1)))
Y2=I(i)+A(i)*(X2-J(i))
end
coord=[X1(:),Y1(:),X2(:),Y2(:)]
%coord
writematrix(coord,'Coord_15.csv')
I am trying to save the coordinates (X1, X2, Y1,Y2) from a for loop as shown in the code above. All inputs (I, J, A, D) are columns vectors , but i only the last iteration is saved. I will appreciate any help.
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Respuesta aceptada
Sulaymon Eshkabilov
el 12 de Mayo de 2019
Hi,
Simply add (i) after your output variables, viz. X1, Y1, X2, Y2:
for i=1:1500
X1(i)=J(i)-sqrt((D(i)^2)/((sqrt(A(i))+1)))
Y1(i)=I(i)-A(i)*(J(i)-X1)
X2(i)=J(i)+sqrt((D(i)^2)/((sqrt(A(i))+1)))
Y2(i)=I(i)+A(i)*(X2-J(i))
end
coord=[X1(:),Y1(:),X2(:),Y2(:)]
%coord
writematrix(coord,'Coord_15.csv')
Good luck
4 comentarios
madhan ravi
el 16 de Mayo de 2019
Editada: madhan ravi
el 16 de Mayo de 2019
Then why did you accept the answer if it doesn’t solve the problem??
Sulaymon Eshkabilov
el 16 de Mayo de 2019
Before commenting any point verify what you have stated. That is the correct answer. Vectorization is another solution.
Más respuestas (1)
madhan ravi
el 12 de Mayo de 2019
Editada: madhan ravi
el 16 de Mayo de 2019
You don't need a loop , this is straight forward just vectorize your code:
Note: The other answer doesn‘t show the importance of preallocation.
X1=J-sqrt((D.^2)./((sqrt(A)+1)));
Y1=I-A.*(J-X1);
X2=J+sqrt((D.^2)./((sqrt(A)+1)));
Y2=I+A.*(X2-J);
coord=[X1(:),Y1(:),X2(:),Y2(:)];
writematrix(coord,'Coord_15.csv')
2 comentarios
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