if f(t)=1/t find the average rate of f with respect to t over the intervals from t=2 to t=3

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syms t
f(t)=1/t;
t=2;
t=3;
f(3)-f(2)/3-2
disp(t)
  2 comentarios
Geoff Hayes
Geoff Hayes el 3 de Ag. de 2019
karthik - what exactly is your question? Why do you have this line of code
f(3)-f(2)/3-2
? Is this supposed to be your average (though isn't being assigned to anything)? Be careful here...you may want to add some brackets around the numerator and denominator...
KALYAN ACHARJYA
KALYAN ACHARJYA el 3 de Ag. de 2019
Editada: KALYAN ACHARJYA el 3 de Ag. de 2019
Is this?
syms t
f(t)=1/t;
t=2;
t=3;
ft_averg=(f(3)-f(2))/(3-2);
disp(ft_averg);

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Respuestas (1)

Navya Seelam
Navya Seelam el 6 de Ag. de 2019
Editada: Navya Seelam el 6 de Ag. de 2019
Hi,
Do you want to find average rate or average? Method to find both is given below
syms t
f=@(t) 1./t;
tmin=2;
tmax=3;
average_rate=(f(3)-f(2))/(tmax-tmin) % average rate of f(t) with respect to t
average=integral(f,tmin,tmax)/(tmax-tmin) % average of f(t)

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