Store results of for loop in matrix

ab=[X01(:) X02(:) a(:) m(:) b(:)];

Countcell=zeros(1, length(ab))
for i=1:length(ab)
    X=[(ab(i,1)+(0:(ab(i,3)/dx):ab(i,3))*1),ab(i,2)]
    Y=(ab(i,4).*X)+ab(i,5)
    ncol=fix(X./CS)+1;
    ncol=[ncol].';
    nrow=fix(Y./CS)+1
    nrow=[nrow].';
    Ncell=[ncol, nrow]
    Countcell=Ncell(i)  
end  

I am trying to store all the results of a for loop into one matrix. At each iteration, the result is an (n by 2) matrix. I cant use cell2mat because these matrices have different lengths. I have tried to pre-allocate, but without success.

Answer 1

[Stephen23]

Use a cell array:

N = numel(ab);
out = cell(1,N); % preallocate cell array.
for k = 1:N
    ... your code
    out{k} = Ncell;
end
mat = vertcat(out{:}) % optional.

https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-cell-array.html

https://www.mathworks.com/help/matlab/matlab_prog/comma-separated-lists.html

https://www.mathworks.com/matlabcentral/answers/320713-how-to-operate-on-comma-separated-lists

[Tchilabalo]

It works. Thanks.