using textscan to find the rest of the line after the specific expression...

file = uigetfile('*.txt','Select the text file to parse');
fid=fopen(file)
text=fileread(file)

I have a really long complicated text file that I want to parse. It is really long and is a list of lines. There are no comma delimiters, but the machine name that I am looking for is always at the end of the line ... like

121212323 : Machine Name = roboDog
121222323 : Machine IOS = Android

The code above was my attempt to desplay the lines which contained the keyword. It wouldn't work, but I would ideally like each Machine Name to be stored in a vector like machineName={'roboDog' ; 'roboCat'}

Thanks!

[the cyclist]

Isn't this identical to your question here? Or did I miss something subtle?

Answer 1

[Image Analyst]

Try this:

% Open the file.
fileID = fopen(fullFileName, 'rt');
% Read the first line of the file.
textLine = fgetl(fileID);
machineName = {}; % Initialize to null
while ischar(textLine)
	% Print out what line we're operating on so we can see it.
	fprintf('%s\n', textLine);
     if contains(textLine, ' : Machine Name', 'IgnoreCase', true)
         % Line of text included Machine.  Get stuff after the equal sign and strip off any leading and trailing spaces.
         equalLocation = strfind(textLine, '= ')
         machineName{end+1} = strtrim(textLine(equalLocation + 1 : end))
     end
	% Read the next line.
	textLine = fgetl(fileID);
end
% All done reading all lines, so close the file.
fclose(fileID);

machineName is your cell array of strings.

Answer 2

[the cyclist]

The code I posted in your other question ...

text=fileread(fileName);
expr='(?<=Name = )\w*';
machineName=regexp(text, expr,'match');

gives the same result in machineName as Image Analyst's answer, in a couple simple tests.