Check if a set of coordinates are on a line

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Sebastian Ursarescu
Sebastian Ursarescu el 18 de Sept. de 2019
Comentada: Sebastian Ursarescu el 18 de Sept. de 2019
I have a set of coordinates, for example x = [0 0 0 0] y = [1 0.9 1.1 1] or x = [1 2 3 4] y = [1 4 6 7], and I want to know if they are almost on a line. I can say the first exemple does and the second doesn't.
I tried with polyarea checking if the area is small enough but it's hard to define the crossing area value regarding the size of the polygon and, moreover, it gives the wrong answer if the polygon crosses itself, like in the first example.
Thank you in advice.
  1 comentario
KALYAN ACHARJYA
KALYAN ACHARJYA el 18 de Sept. de 2019
@Guillaume sir, sorry, I missed it, I misundestood the question and considering on image (Horizantal or Vertical line)
Always Thanks

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Respuesta aceptada

Bruno Luong
Bruno Luong el 18 de Sept. de 2019
Editada: Bruno Luong el 18 de Sept. de 2019
xy=[x(:)';y(:)'];
criteriatol = 0.01; % adjust to your need, smaller means stricter line test
s = svd(xy-mean(xy,2));
isline = max(s)*criteriatol>min(s)
Work isotropically (orientation independent, but also scaling, shifting independent), even with vertical line.

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Guillaume
Guillaume el 18 de Sept. de 2019
Probably, the best way is to use polyfit (which does a least square fit) and look at the norm of the residuals. If it's small enough your points (tolerance is up to you) are on a line.
[~, pfit] = polyfit(x, y, 1); %least square fit of a line
if pfit.normr <= arbitrary_value
disp('is a line');
else
disp('not a line');
end
You may need to special case when all the x are (almost) all equal (vertical line) if that's an actual possibility.
  2 comentarios
Sebastian Ursarescu
Sebastian Ursarescu el 18 de Sept. de 2019
The problem is actually when I have a vertical line. I already tried using functions but they don't cover the case of vertical line
Guillaume
Guillaume el 18 de Sept. de 2019
Then use Bruno's answer which is a lot better than mine anyway.

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