problems using && with dropdown list result
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Muazma Ali
el 24 de Sept. de 2019
Editada: Muazma Ali
el 24 de Sept. de 2019
hi!
S={'NH4Cl'; 'MgCl2'; 'CaCl2'; 'ZnCl2'; 'ZnSO4'; 'NaCl'};
>> str={'Choose the combinations of salts available'};
>> result=listdlg('Promptstring',str, 'ListSize', [100,100], 'ListString', S, 'SelectionMode', 'multiple');
>> if result==1&&result==3
disp('hei')
end
the error I get: Operands to the || and && operators must be convertible to logical scalar values. Donnt understand because the output from result is scalar and is should be possible to use && togehter with scalar outputs..
4 comentarios
the cyclist
el 24 de Sept. de 2019
Muazma,
The problem with your code is clear to me (and Adam). You have allowed the user to select multiple items. For example, they might select 'NH4Cl' and 'CaCl2'. In this case,
result = [1 3]
and you are trying to evaluate
[1 3]==1 && [1 3]==3
which is
[1 0] && [0 1] % these are logical vectors
These are not allowable operands for the short-circuit logical operators. The operands must each be a single scalar value.
What is not clear to me is what you want to happen in your if statement. Perhaps you could explain this more completely.
Respuesta aceptada
the cyclist
el 24 de Sept. de 2019
Here is what I think you want, based on your most recent comment:
if all(ismember([1 3],result))
disp('hei')
end
The if statement will be entered if the user's selections include 'NH4Cl' and 'CaCl2'.
0 comentarios
Más respuestas (1)
the cyclist
el 24 de Sept. de 2019
My best guess as to what you want is
if any(ismember(result,[1 3]))
disp('hei')
end
The if statement will be entered if the user's selections include 'NH4Cl' or 'CaCl2' (or both).
2 comentarios
Guillaume
el 24 de Sept. de 2019
Maybe the OP wants all instead of any. I.e all the selections must be NH4Cl or CaCl2
if all(ismember(result, [1 3]))
Ver también
Categorías
Más información sobre Loops and Conditional Statements en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!