# Create a sequence based on other arrays

2 views (last 30 days)
luca on 3 Oct 2019
Commented: Nipun Katyal on 2 Mar 2020
Given the arrays
SP = [1 2 4 6 7 9 10]
V = [5 20 10 15 5 20 10 ]
I want to create a random array P that contain the elements of SP repeated as many times as is indicated in V. So the element one has to be repeated 5 times, two repeated 20 times, four repeated 10 times and so on.
An important rule to respect is that at maximum we can mix two elements at time, respecting the order indicated in V. So the first elements in the random sequence will be 1 and 2, 4 can appear just when one between 1 and 2 will be terminated.
Let's see an example:
P = [1 1 2 1 2 1 2 2 1 2 2 4 2 4 2 4 2 4 4 2 2 4 2 2 4 4 2 2 4 4 2 6 2 6 2 6 6 2 6 2 6 6 7 6 7 7 6 6 7 6 6 7 6 9 6 9 6 9 9 10 10 9 9 10 9 9 10 9 9 10 9 9 10 9 9 10 9 9 10 10 9 9 10 9 9]
As we can see as soon as 1 has been repeated 10 times, then 4 appears in the sequence in combination with 2. Then again is 4 that terminated before 2 and 6 enters in the sequence with 2.
May someone help me with this task?

Nipun Katyal on 2 Mar 2020
You can do this by maintaining two variables to store the current two indices until the correponding elements in V are exhausted, I hope this helps.
##### 2 CommentsShowHide 1 older comment
Nipun Katyal on 2 Mar 2020
Yes it is supposed to be idy

R2019b

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