Function to check if a number is divisible by 5

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hna
hna el 13 de Oct. de 2019
Editada: Walter Roberson el 30 de Mzo. de 2023
How can I write a function m.file that takes as input a real number and checks to see if it is divisible by 5. An appropriate message indicating the result should be the output.
I have tried to write this but it dosen't seem to work as I need the user to input a number and check if it is divisble by 5
function [resp] = div5(x)
if (rem(x,5) == 0)
resp = 1;
else
resp = 0;
end
Thanks in advance
  4 comentarios
Walter Roberson
Walter Roberson el 13 de Oct. de 2019
No you would use the code from before and then at the command line
div5(10)
Fahrizal Nurcahya
Fahrizal Nurcahya el 15 de Oct. de 2020
Editada: DGM el 30 de Mzo. de 2023
bro it must be like this, check it my function
function [a] = div5(x)
% [x] = div5(x) - to checks a real number if it is divisible by 5.
for a=rem(x,5)
if a~=0
[a] ='NOT divisible by 5.';
else
[a] ='divisible by 5.';
end
end
end

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Respuestas (1)

AKASH KUMAR
AKASH KUMAR el 29 de Mzo. de 2023
Editada: DGM el 30 de Mzo. de 2023
% check "a" is divisible by "b" or not
function test = divisibility_test(a,b)
if ceil(a/b)-a/b==0
test = true;
else
test=false;
end
end
  1 comentario
DGM
DGM el 30 de Mzo. de 2023
The output of
ceil(a/b)-a/b==0
is a logical array, and the first conditional is only executed if every element of that array is true. So the whole thing simplifies to
function test = divisibility_test(a,b)
test = all(ceil(a/b)-a/b==0);
end
or just
function test = divisibility_test(a,b)
test = all(~mod(a,b));
end

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