# If statement with or condition

4 views (last 30 days)
luca on 15 Oct 2019
Answered: Fabio Freschi on 15 Oct 2019
Hi given the following code
BDR= [175 175 175 175 175 175 175 175 175 175 175 175 175];
SETTIMANA=[190 130 120 140 100 160 175 165 157 140 130 175 140 ];
NEXTpro = [25 60 50 40 30 30 30 35 10 34 23 45 12];
if (SETTIMANA(1) < BDR (1)) | (SETTIMANA(2)< BDR(2)) | (SETTIMANA(3)< BDR(3)) | (SETTIMANA(4)< BDR(4))| (SETTIMANA(5)< BDR(5))| (SETTIMANA(6)< BDR(6))| (SETTIMANA(7)< BDR(7))| (SETTIMANA(8)< BDR(8))| (SETTIMANA(9)< BDR(9)) | (SETTIMANA(10)< BDR (10)) | (SETTIMANA(11)< BDR(11))| (SETTIMANA(12)< BDR(12)) | (SETTIMANA(13)< BDR(13));
Y=NEXTpro
else
Y=NEXTpro
SETT1 = SETTIMANA(1:numel(BDR)); % Equalise Vectors
Y = Y(1:numel(BDR)); % Equalise Vectors
idxy = SETT1 <= BDR; % Logical Index Vecto
Y=BDR - SETT1;
Y=Y.*idxy
end
I cannot understand why the if condition cannot read the or operator in the right way.
The conditin is: if I have a value in SETTIMANA that exceed the value in BDR in the same column, then switch to condition else.
##### 2 CommentsShowHide 1 older comment
KALYAN ACHARJYA on 15 Oct 2019
Its perfectly working as you mentioned
If any element of SETTIMANA< correcponding NEXTpro
%...^...Note here
% do
else
%do
end
or
If all element of SETTIMANA< correcponding NEXTpro
%...^...Note here
% do
else
%do
end
Which one
Also you can use logical indexing directly without mentioning one by one of SETTIMANA and NEXTpro

Fabio Freschi on 15 Oct 2019
if any(settimana < bdr)
...
else
...
end

R2019b

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