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replacing sequences in matrix

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xRobot on 22 Nov 2019
Commented: Image Analyst on 23 Nov 2019
Hello, in the code below I am attempting to do the following:
yourarray = ['hood'; 'hope'; 'make';];
guess = input('Enter a four letter word: ');
yourarray(ismember(yourarray, 'guess', 'rows'), :) = [];
  1. Take in user input for a four letter word
  2. Remove the four letter input from the matrix then display the resulting matrix with the user input removed
I have had no luck. I am trying make it so that I can remove any sequence letter the user chooses for instance, instead of one of the three words in the matrix he may choose "mope". How can I better accomplish this? Any advise is greatly appreciated. I have tried other methods but landed on this one as being what I think will be the closest possible solution. Thanks for any help!


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Answers (1)

Image Analyst
Image Analyst on 22 Nov 2019
Try this:
yourarray = {'hood'; 'hope'; 'make'}; % Cell array.
guess = input('Enter a four letter word: ', 's'); % Use 's' option.
index = ismember(yourarray, guess, 'rows')
if all(index == 0)
% All zeros mean it was not found.
message = sprintf('%s was not found in the list.', guess);
% If any element of index is 1 then it was found at that row.
row = find(index)
yourarray(row, :) = [];


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Image Analyst
Image Analyst on 23 Nov 2019
Did you try strfind(), strrep(), or contains()? So the letters don't have to be contiguous? What if the 4 letters occur in hundreds of locations? Replace the letter wherever it appears with a space with strrep()????
xRobot on 23 Nov 2019
No the letters can be found and combined from anywhere in the block. That is the basis of the game to find hidden four letter words in a scrambled block of letters.
Image Analyst
Image Analyst on 23 Nov 2019
And what about my first question in my last comment?

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