Creating an array from 1 to n

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Agnieszka Polak
Agnieszka Polak el 20 de Dic. de 2019
Comentada: Hans Henning Erle el 17 de Nov. de 2021
Hello!
I am trying to create an array of integers from 1 to n [1 2 3 ..... n], where n is a variable that can change.
How should I approach that?
Thank you!
  3 comentarios
Luis Benitez Prieto
Luis Benitez Prieto el 27 de Jul. de 2021
It is elemantary but also not. If you look at the accepted answer below. The answer is creating a double array, the numbers inside are integer values, but not of interger format.
I actually was interested in this question because when I want to create an array of integers I do not want to create a double array in the process by doing something like:
uint32([1:10])
Instead, I would like to directly create an integer array. And thats something I have not easily found in the documentation and a legit question in my opinion. Perhaps thats what the poster is asking for.
Stephen23
Stephen23 el 27 de Jul. de 2021
Editada: Stephen23 el 27 de Jul. de 2021
@Luis Benitez Prieto: like this:
V = uint32(1):uint32(10)
V = 1×10
1 2 3 4 5 6 7 8 9 10
class(V)
ans = 'uint32'
Note that just one uint32 input is sufficient to define the output as uint32:
class(uint32(1):10)
ans = 'uint32'
class(1:uint32(10))
ans = 'uint32'
Note that the square brackets in your example are superfluous and misleading:

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Alex Mcaulley
Alex Mcaulley el 20 de Dic. de 2019
n = 10 %
1:n
ans =
1 2 3 4 5 6 7 8 9 10
  2 comentarios
Rui
Rui el 30 de Oct. de 2021
Editada: Rui el 30 de Oct. de 2021
how can i get it in reverse order also with a 0 in end?
like this
10 9 8 7 6 5 4 3 2 1 0
Hans Henning Erle
Hans Henning Erle el 17 de Nov. de 2021
10:-1:0

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