Interp3. Error using griddedInterpolant. The grid vectors do not define a grid of points that match the given values.
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Hi,
I'm trying to use interp3(x, y, z, image, xq, yq, zq).
My new query xq, yq and zq are [256, 256, 90], and my old x, y and z are equal to [196,256,512].
I get the following error
Error using griddedInterpolant
The grid vectors do not define a grid of points that match the
given values.
Error in interp3 (line 146)
F = griddedInterpolant(X, Y, Z, V, method,extrap);
Error in clinicalTest_aligment (line 99)
newMrImg = interp3(X, Y, Z, oldImage, Xq, Yq, Zq);
It does not work because the x is smaller than xq?
In that case it is 'extrapolation' and not interpolation?
Thanks in advance
3 comentarios
Adam Danz
el 20 de Feb. de 2020
I do extracellular recordings so I've spent a lot of time (4-6 hrs a day for years) listening to spike trains of visually responsive neurons (MSTd) firing in real time to various visual stimuli. I've always thought it would be cool to combine segments of those audible responses to dubstep music :D
Respuestas (1)
Adam Danz
el 20 de Feb. de 2020
Editada: Adam Danz
el 20 de Feb. de 2020
Follow this tutorial and if you get stuck or come across a problem that isn't already addressed in the forum I'd be glad to dig in. If you're working with an image of uint8 data, you'll need to convert it to double, first.
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