invert the function s = L(t) to solve for t.

syms t;
x(t)= sin(3*t^2)*(12*t + (10*13^(1/2))/13);
y(t)= t*(6*13^(1/2)*t + 5);
z(t)= cos(3*t^2)*(12*t + (10*13^(1/2))/13);

syms tau;
L(t) = vpaintegral(speed(tau), tau, 0, t);

syms s;
solve(s == L(t), t);

I'm trying to invert the function s = L(t) to solve for t, but I don't know how to change the function regarding as t.

[Nishant Gupta]

Can you please tell what is speed(tau)?