Time varying force with ode23

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Hi there
I have the following code:
tf = 1;
t = linspace(0,3);
Ft = zeros(length(t),1);
% Here I generate the force values at different time intervals.
for i = 1:length(t)
if t(i) <= tf
Ft(i) = Fo*sin(2*pi*t(i)/tf);
elseif t(i) > tf
Ft(i) = 0;
ic = [0, 0]; % Initial conditions
dXdt = @(t, x) [x(2);
Ft * 1/(m1+m2)];
[t, x] = ode23(dXdt, [0, 3], ic);
I'm struggling to incorportate this time varying force F(t) into the ode23 function.
Any help as to how I can maybe get this done?
Thanks in advance!

Accepted Answer

darova on 25 Apr 2020
Use function handle
Ft = @(t) (t<=tf)*Fo*sin(2*pi*t/tf);
dXdt = @(t, x) [x(2);
Ft(t) * 1/(m1+m2)];
Christo van Rensburg
Christo van Rensburg on 25 Apr 2020
It seems to work though.
Walter I'll try your method now, because what you're saying makes sense.
Thanks for the help!

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More Answers (1)

Walter Roberson
Walter Roberson on 25 Apr 2020
You cannot do that the way you want. The ode* routines cannot handle discontinuities in the driving functions. You need to break it up into two time periods, one with the force and one without the force.
tf = 1;
dXdt_F = @(t, x) [x(2); Fo*sin(2*pi*t/tf) / (m1+m2)];
dXdt_NF = @(t, x) [x(2); 0];
ic = [0, 0]; % Initial conditions
[t1, x1] = ode23(dXdt_F, [0, tf], ic);
ic2 = x1(end,:);
[t2, x2] = ode23(dXdt_NF, [tf, 3], ic2);
t = [t1; t2(2:end)];
x = [x1; x2(2:end,:)];
  1 Comment
Christo van Rensburg
Christo van Rensburg on 25 Apr 2020
Both methods seem to work fine.
Thanks guys.

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