Time varying force with ode23

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Christo van Rensburg
Christo van Rensburg el 25 de Abr. de 2020
Comentada: Christo van Rensburg el 25 de Abr. de 2020
Hi there
I have the following code:
tf = 1;
t = linspace(0,3);
Ft = zeros(length(t),1);
% Here I generate the force values at different time intervals.
for i = 1:length(t)
if t(i) <= tf
Ft(i) = Fo*sin(2*pi*t(i)/tf);
elseif t(i) > tf
Ft(i) = 0;
end
end
ic = [0, 0]; % Initial conditions
dXdt = @(t, x) [x(2);
Ft * 1/(m1+m2)];
[t, x] = ode23(dXdt, [0, 3], ic);
I'm struggling to incorportate this time varying force F(t) into the ode23 function.
Any help as to how I can maybe get this done?
Thanks in advance!

Respuesta aceptada

darova
darova el 25 de Abr. de 2020
Use function handle
Ft = @(t) (t<=tf)*Fo*sin(2*pi*t/tf);
dXdt = @(t, x) [x(2);
Ft(t) * 1/(m1+m2)];
  2 comentarios
Walter Roberson
Walter Roberson el 25 de Abr. de 2020
That would work if the driving force was not discontinuous.
Christo van Rensburg
Christo van Rensburg el 25 de Abr. de 2020
It seems to work though.
Walter I'll try your method now, because what you're saying makes sense.
Thanks for the help!

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Más respuestas (1)

Walter Roberson
Walter Roberson el 25 de Abr. de 2020
You cannot do that the way you want. The ode* routines cannot handle discontinuities in the driving functions. You need to break it up into two time periods, one with the force and one without the force.
tf = 1;
dXdt_F = @(t, x) [x(2); Fo*sin(2*pi*t/tf) / (m1+m2)];
dXdt_NF = @(t, x) [x(2); 0];
ic = [0, 0]; % Initial conditions
[t1, x1] = ode23(dXdt_F, [0, tf], ic);
ic2 = x1(end,:);
[t2, x2] = ode23(dXdt_NF, [tf, 3], ic2);
t = [t1; t2(2:end)];
x = [x1; x2(2:end,:)];
  1 comentario
Christo van Rensburg
Christo van Rensburg el 25 de Abr. de 2020
Both methods seem to work fine.
Thanks guys.

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