Why did I get different results by using degree/radiance as the unit in the integration?

4 views (last 30 days)
today I wonder if the unit (degree/radiance) of integration variable matters in Matlab, so I tried these 2 peices of codes:
x_tst=0:0.1:180; % in degree
y_tst=sind(x_tst);
Q1=trapz(x_tst,y_tst)
Q1 =
1.145915299373423e+02
x_tst_deg=0:0.1:180;
x_tst_rad=x_tst_deg./180.*pi;% in radiance
y_tst=sin(x_tst_rad);
Q2=trapz(x_tst_rad,y_tst)
Q2 =
1.999949230172279
As you can see, the results are different, could someone tell me why we have this problem in MATLAB?
Must we use radiance as the unit of angle in Matlab (especially in the integration)?
What if I would like to adopt 'degree' as the unit of the integration variable?

Accepted Answer

KSSV
KSSV on 23 Jun 2020
Edited: KSSV on 23 Jun 2020
Note that both the results are same...but they are in different units....
Your Q1 is in degrees and Q2 is in radians.....Convert them to the same units and see...
% Check in degrees
Q2*180/pi
Q1
% check in radians
Q1*pi/180
Q2
  4 Comments
KSSV
KSSV on 23 Jun 2020
Simple man...your x-values i.e x_tst are in radians for Q1 and are in degrees for Q2...as the area is length*breadth...your x-values are different in both the cases...so your values are different.

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by