Concatenate cells: making column and row headers

Hi,

I have a column and a row like this:

   col={'cat1'; 'cat2'; 'cat3'}
   row={'mouse1' 'mouse2' 'mouse3'}

I would like to make these as column and row headers (eventually for a table) like this such that my table looks like this:

I've attempted to use cat such that:

   table=cat(2,col,row)

but it results in an error the dimensions are not consistent..

Thank you so much for your help and please let me know if I am not clear.

[Azzi Abdelmalek]

Your image is invisible

[Mich]

Oh! that is weird, here is the link: http://imgur.com/y0wyb I'm sorry!

Answer 1

[Pedro Villena]

 table(2:numel(row)+1)   = row;
 table(2:numel(col)+1,1) = col;

[Mich]

That's it! The way that gave me the exact result was:

   table(1:numel(row))=row;
   table(1:numel(col),1)=col;

Thank you so much!! And to all the helpers, you are awesome!

Answer 2

[Honglei Chen]

table(2:4) = row;
table(2:4,1) = col;

[Mich]

Unfortunately i get a dimension mismatch error as well. I tried the method under Azzi's comment because with my real dataset I would not know the if it actually ended on the 4th row. Perhaps I am looking for something more like:

   table={}
   table(2:size(row,2))=row;
   table(2:size(col,1),1)=col;

But I get a dimension mismatch.. Thank you for your response!!

[Honglei Chen]

The code below works fine for me. If you get an error, you may need to make sure that your variable, table, is not defined previously with other dimensions. If that still didn't work out, please post your example with the error message.

>> col = {'a','b','c'}

col = 

      'a'    'b'    'c'

>> row = {'d','e','f'}

row = 

      'd'    'e'    'f'

>> table(2:numel(row)+1) = row

table = 

      []    'd'    'e'    'f'

>> table(2:numel(col)+1,1) = col

table = 

       []    'd'    'e'    'f'
      'a'     []     []     []
      'b'     []     []     []
      'c'     []     []     []

Answer 3

[Matt Fig]

row={'cat1'; 'cat2'; 'cat3'};
col={'mouse1' 'mouse2' 'mouse3'};
figure
t = uitable('Data',[],...
            'ColumnName',col,... 
            'RowName',row,...
            'Position',[20 20 360 100])