Loop for adding matrix elements

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Lev Mihailov
Lev Mihailov el 28 de Jul. de 2020
Comentada: dpb el 29 de Jul. de 2020
Hello! I have a matrix, in each column I need to add several elements (rows) of different lengths to the end of the column
X=rand(577,1289) % my matrix
LimitOneStep = 0.012 % the step I need to summarize
% columlim
for i=1:10 % start of cycle
count=0 % basic counter for measuring column length (row count)
sum=0 % counter for the sum of one part of a column (add multiple rows)
LimitOne=1 % the number of lines that I need to summarize according to the step above
for j=1:544 % this is a measure of the read limit on the column (544 is the number of rows for each column)
while count<LimitOne % the very condition when my number of steps does not exceed one. it's about 83 rows per column
count=count+LimitOneStep % summarizes the step to service
countS=ceil(count/LimitOneStep ) % allows you to get an integer, because in a loop, the index cannot be a fractional number
sum=sum+X(i,countS)
end
XS(i,j)=sum;
sum=0;
end
end
Index in position 2 exceeds array bounds (must not exceed 1289).
Error in SumX(line 890)
sum=sum+X(i,countS)
writes this error, help me figure it out
  7 comentarios
Lev Mihailov
Lev Mihailov el 29 de Jul. de 2020
X=[2 2 2 2 ; 3 3 3 3 ; 4 4 4 4 ; 5 5 5 5 ; 2 2 2 2 ]
countS=2 % does not count the last line
SX=[5 5 5 5; 9 9 9 9] % this is the answer I want to receive
dpb
dpb el 29 de Jul. de 2020
And what logic explains how one would arrive at that result from the input, pray tell?
Simply repeating nonworking code does nothing to explain the underlying rationale behind the desire.
"Can't code what can't explain"

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