Best way to present histogram with different realisation number

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I have two data sets as attached with different number of realisations and i want to compare between them. So, I created their histograms to present their realisations over each other’s as in the figure. However, it is hard to see the difference as the number of frequencies is different. Anyway, to present this better; maybe normalising it. Not really sure!
x1 = NPV_1000;
y1 = NPV_10000;
h1 = histogram(x1);
hold on
h2 = histogram(y1);
xlabel('NPV ($B)')

Accepted Answer

Arthur Roué
Arthur Roué on 29 Jul 2020
You can normalize directly with histogram function by changing Normalization property.
h1 = histogram(x1, 'Normalization', 'probability');
Arthur Roué
Arthur Roué on 29 Jul 2020
You're welcome. Check for histogram property in documentation, you can control appearance in many ways.
For bin numbers, use 2nd argument :
h1 = histogram(x1, nbBins, 'Normalization', 'probability');

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More Answers (1)

Steven Lord
Steven Lord on 29 Jul 2020
In the "Plot Multiple Histograms" example on the documentation page for histogram, we show one way to give two histogram objects consistent bins. Another way would be to set the BinEdges property (or specify the edges input) for one of the histogram objects using the BinEdges property of the other.
x = randn(1, 1e5);
y = 1 + randn(1, 1e5);
h1 = histogram(x);
hold on
h2 = histogram(y, h1.BinEdges);


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