repeat elements of row matrix li [1 2 2 3 3 3 4 4 4 4 n...... n times]

creat a row matrix like

n=input

eg n=4

row=[1 2 2 3 3 3 4 4 4 4 ]

[Adam Danz]

Response to your edited question:

Now the problem is very easy, see the last example in my answer.

Answer 1

[KSSV]

n = 6 ; 
p = cumsum(10.^(0:n-1)) ;
iwant = p.*(1:n)

[Ankush Kumar]

is it work for 12

[KSSV]

n = 10 ; 
iwant = cells(1,n) ; 
for i = 1:n
  iwant{i} = (repmat(num2str(i),1,i)) ;
end
iwant

Answer 2

[Adam Danz]

If you want the output to be character vectors,

n = 12; 
y = arrayfun(@(n){repmat(num2str(n),1,n)},1:n);

% Output Sample: 
% y =
%   1×12 cell array
%   Columns 1 through 10
%     {'1'}    {'22'}    {'333'}    {'4444'}    {'55555'}    {'666666'}    {'7777777'}    {'88888888'}  ....

If you want the output to be numeric,

n = 12;
y = cell2mat(arrayfun(@(n){str2double(repmat(num2str(n),1,n))},1:n));

% Output Sample:
format longg
% y = 1 22 333 4444 55555 666666 7777777 88888888 999999999 1.01010101010101e+19 1.11111111111111e+21 1.21212121212121e+23

If you want the output to be numeric and match the format of your updated question,

n = 12; 
y = repelem(1:n, 1:n);

% Output
% y =
%   Columns 1 through 26
%      1     2     2     3     3     3     4     4     4     4     5     5     5     5     5     6     6     6     6     6     6     7     7     7     7     7
%   Columns 27 through 52
%      7     7     8     8     8     8     8     8     8     8     9     9     9     9     9     9     9     9     9    10    10    10    10    10    10    10
%   Columns 53 through 78
%     10    10    10    11    11    11    11    11    11    11    11    11    11    11    12    12    12    12    12    12    12    12    12    12    12    12