Set of sequnce number

If I have this list of number A = [1,2,3,4,5,6,7,8] I want these number become as 12345678 and covert to hex number.

Answer 1

[Fangjun Jiang]

%%
A=1:8;
N=numel(A);
Multiply=10.^(N-1:-1:0)';
B=A*Multiply
C=dec2hex(B)

[Dhafar hamed]

Thank u very much

Answer 2

[Ameer Hamza]

If the number is not very large, then use

A = [1,2,3,4,5,6,7,8];
n = numel(A);
num = 10.^(n-1:-1:0)*A.';
hex = dec2hex(num);

However, if the number is large then you will need symbolic toolbox

A = sym([1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9]);
n = numel(A);
num = 10.^(n-1:-1:0)*A.';
hex = dec2hex(num);

[Dhafar hamed]

6thank you very much

[Dhafar hamed]

It is work but if I have 50 number then hex DOS not work

[Ameer Hamza]

It is working on my system

A = sym([1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9]);
n = numel(A);
num = 10.^(n-1:-1:0)*A.';
hex = dec2hex(num);

Result

>> num
num =
123456789123456789123456789123456789123456789123456789123456789123456789123456789123456789123456789123456789
>> hex
hex =
    'D750EB5568D054990864A04EEEFA6323673AEBD63A4AD487F13BFE74B7FC29A13A5F57B73C72870B684045F15'

[Dhafar hamed]

Thank you very much I don't know why its DOS not work with me

Answer 3

[Bruno Luong]

>> A = [1,2,3,4,5,6,7,8]

A =

     1     2     3     4     5     6     7     8

>> polyval(A,10)

ans =

    12345678

[Dhafar hamed]

It is give only one number