what y(2) ,y(3), y(4) , y(5) ,by using matlab ?
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
y(0)=1 y(2)=5
y(n+2)=3y(n+1)-5y(n)
what y(2) ,y(3), y(4) , y(5) ,by using matlab ?
4 comentarios
Stephen23
el 19 de Sept. de 2020
"what y(2) ,y(3), y(4) , y(5) ,by using matlab ?"
y(0)=1 y(2)=5
y(n+2)=3y(n+1)-5y(n)
what y(2) ,y(3), y(4) , y(5) ,by using matlab ?
Respuestas (1)
Alan Stevens
el 19 de Sept. de 2020
You need to start with y(1) = 1, not y(0) = 1. Then with y(2) = 5, you can use a for loop:
for n=1:3, y(n+2) = 3*y(n+1)-5*y(n); end
3 comentarios
Walter Roberson
el 19 de Sept. de 2020
Editada: Walter Roberson
el 19 de Sept. de 2020
you did not loop like I suggested. You tried to vectorize.
The function can only be vectorized after a bunch of mathematical calculations to figure out the general form. I recommend looping, it is much easier.
Ver también
Categorías
Más información sobre Loops and Conditional Statements en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!